REFERENCE
EQUATIONS
Every equation, what it solves, when to use it.
v = v_0 + at
Velocity–Time Relation
Gives the velocity of an object after it has been accelerating at a constant rate for a time t. Use
d = v_0 t + \tfrac{1}{2}at^2
Position–Time Relation
Gives the displacement of an object under constant acceleration after a time t. Use it when you need
v^2 = v_0^2 + 2ad
Kinematic v² Relation
Links initial velocity, final velocity, and displacement without requiring time. The equation is the
v_{close} = v_A + v_B
Relative Velocity (1D, Head-On)
Gives the closing speed of two objects moving directly toward each other. The time to collision is t
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
Quadratic Formula
Solves any equation of the form ax² + bx + c = 0 for x. In kinematics it appears whenever you set tw
v_x = v_0\cos\theta,\; v_y = v_0\sin\theta
Velocity Decomposition
Splits a launch velocity into independent horizontal and vertical components. Once decomposed, horiz
T = \frac{2v_0\sin\theta}{g}
Projectile Time of Flight
Gives the total airborne time for a projectile launched from and landing on the same horizontal leve
R = \frac{v_0^2\sin 2\theta}{g}
Projectile Range
Gives the horizontal distance a projectile travels before returning to its launch height. Optimal ra
H = \frac{(v_0\sin\theta)^2}{2g}
Projectile Peak Height
Gives the maximum height reached by a projectile above its launch point. At the peak, the vertical v
v = v_0 + at,\; d = v_0 t + \tfrac{1}{2}at^2,\; v^2 = v_0^2 + 2ad
1D Kinematic Equations (Constant Acceleration)
Three interrelated equations — v = v_0 + at, d = v_0·t + ½at², v² = v_0² + 2ad — collectively cover
\sin 2\theta = \sin(\pi - 2\theta)
Complementary Angles (Equal Range)
Shows that two launch angles that sum to 90° — for example 30° and 60° — produce identical horizonta
F = ma
Newton's Second Law
Relates net force, mass, and acceleration. Given any two of the three quantities, the equation yield
W = mg
Weight Equation
Gives the gravitational force on a mass near Earth's surface. Weight is what a scale reads when the
F_f = \mu N
Friction Force
Gives the maximum static friction or the kinetic friction force on an object in contact with a surfa
F_k = \mu_k N
Kinetic Friction
Gives the friction force on an already-sliding object. Once an object is in motion, kinetic friction
\sum F = F_1 + F_2 + \cdots
Net Force Summation
States that the net force on an object equals the vector sum of all individual forces acting on it.
F_{12} = -F_{21}
Newton's Third Law
States that every force has an equal and opposite reaction force on a different object. It is the re
F_d = bv
Linear Drag Force (Stokes)
Gives the viscous drag force on a slowly moving sphere in a fluid (Stokes drag): F = bv, where b = 6
F_d = \tfrac{1}{2}\rho C_d A v^2
Quadratic Drag Force (Newtonian)
Gives the aerodynamic drag on a body moving at moderate to high speeds: F = ½ρC_d Av². The drag grow
v_t = \frac{mg}{b}\text{ (linear)},\quad v_t = \sqrt{\frac{2mg}{\rho C_d A}}\text{ (quadratic)}
Terminal Velocity
Gives the constant (maximum) falling speed reached when drag exactly balances gravity. For linear dr
T = 2\pi\sqrt{\frac{L}{g}}
Small-Angle Pendulum Period
Gives the oscillation period of a simple pendulum when the swing amplitude is small (θ₀ ≲ 15°). The
\omega = \sqrt{\frac{g}{L}}
Pendulum Angular Frequency
Gives the angular frequency ω = √(g/L) of a small-angle pendulum. Knowing ω, you can write x(t) = A·
mgh = \tfrac{1}{2}mv^2
Pendulum Energy Conservation
Converts the potential energy at the top of the swing (mgh) into kinetic energy at the bottom (½mv²)
T \approx T_0\!\left(1 + \frac{\theta_0^2}{16} + \frac{11\theta_0^4}{3072}\right)
Small-Angle Period Correction Series
Extends the small-angle pendulum period to larger amplitudes by adding successive correction terms:
T = 4\sqrt{\frac{L}{g}}\,K\!\left(\sin\frac{\theta_0}{2}\right)
Large-Angle Pendulum Period (Exact)
Gives the exact period of a simple pendulum at any amplitude via the complete elliptic integral of t
K(k) = \int_0^{\pi/2}\frac{d\phi}{\sqrt{1-k^2\sin^2\phi}}
Complete Elliptic Integral of the First Kind
Defines K(k) = ∫₀^{π/2} dφ / √(1 − k²sin²φ), a definite integral that appears in the exact large-ang
T = T_0\sum_{n=0}^{\infty}\left[\frac{(2n)!}{2^{2n}(n!)^2}\right]^2\theta_0^{2n}
Taylor Series for Pendulum Period
Expresses the exact elliptic-integral period as a power series in θ₀: T = T₀·Σ [(2n)!/(2²ⁿ(n!)²)]²·θ
x'' + \omega^2 x = 0
Simple Harmonic Oscillator Equation
The universal differential equation x″ + ω²x = 0 describes any system with a linear restoring force.
\omega = \sqrt{\frac{k}{m}}
Spring Angular Frequency
Gives the natural angular frequency of a mass–spring system: ω = √(k/m). From ω you get period T = 2
E = \tfrac{1}{2}kA^2
SHM Total Energy
Gives the constant total mechanical energy of an undamped oscillator: E = ½kA². Energy oscillates be
x(t) = A\cos(\omega t + \phi)
SHM Position
Gives the displacement of a simple harmonic oscillator at any time t: x(t) = A·cos(ωt + φ). The ampl
v(t) = -A\omega\sin(\omega t + \phi)
SHM Velocity
Gives the velocity of a simple harmonic oscillator at any time t: v(t) = −Aω·sin(ωt + φ). It is the
a(t) = -A\omega^2\cos(\omega t + \phi)
SHM Acceleration
Gives the acceleration of a simple harmonic oscillator: a(t) = −Aω²·cos(ωt + φ) = −ω²·x(t). Accelera
\omega_1 = \omega_0,\quad \omega_2 = \sqrt{\omega_0^2 + \omega_C^2}
Coupled Pendulum Normal Modes
Gives the two normal-mode frequencies of two identical pendulums coupled by a weak spring: ω₁ = ω₀ (
x(t) = A_0 e^{-\gamma t/2}\cos(\omega_d t + \phi)
Damped Oscillator Position
Gives the position of an underdamped oscillator: x(t) = A₀·e^(−γt/2)·cos(ω_d·t + φ). The exponential
A(t) = A_0 e^{-\gamma t/2}
Damped Amplitude Decay
Gives the amplitude envelope of a damped oscillator as a function of time: A(t) = A₀·e^(−γt/2). The
Q = \frac{\omega_0}{\gamma}
Quality Factor (Q)
Q = ω₀/γ characterizes how sharply an oscillator resonates. A high Q means narrow bandwidth, slow en
A(\omega_d) = \frac{F_0/m}{\sqrt{(\omega_0^2-\omega_d^2)^2+(\gamma\omega_d)^2}}
Driven Oscillator Steady-State Amplitude
Gives the amplitude of the steady-state response when a force F₀·cos(ω_d·t) drives a damped oscillat
\omega_d \approx \omega_0
Resonance Condition
States that maximum steady-state amplitude occurs when the driving frequency ω_d is close to the nat
\omega_d = \sqrt{\omega_0^2 - \gamma^2/4}
Damped Natural Frequency
Gives the actual oscillation frequency of an underdamped system: ω_d = √(ω₀² − γ²/4). Damping always