Small-Angle Pendulum Period
Gives the oscillation period of a simple pendulum when the swing amplitude is small (θ₀ ≲ 15°)
The equation
What it solves
Gives the oscillation period of a simple pendulum when the swing amplitude is small (θ₀ ≲ 15°). The remarkable result is that T depends only on length and g, not on mass or amplitude.
When to use it
Laboratory pendulums, grandfather clocks, small-angle limit problems. Accurate to within 0.5% for amplitudes below about 15°.
When NOT to use it
Breaks down for large amplitudes — at θ₀ = 30° the error is about 1.7%; at 90° it exceeds 18%. The formula also assumes a massless, inextensible string and a point mass; physical pendulums require the moment of inertia.
Common mistakes
Confusing period T with frequency f or angular frequency ω. Taking L as the string length without adding the radius of the bob. Forgetting the square root — writing T = 2π·L/g instead of T = 2π·√(L/g).
Topics that use this equation
Problems using this equation
- [easy] A simple pendulum hangs from a fixed pivot. The string has length L = 1.2 m and the bob swings throu…
- [medium] A clockmaker needs a pendulum that completes exactly one full oscillation every 3.0 seconds (T = 3.0…
- [hard] A pendulum bob of mass m = 0.5 kg hangs from a string of length L = 0.8 m. It is pulled aside to θ₀ …
- [challenge] A pendulum of length L = 1.0 m is released from rest at θ₀ = 0.6 rad (~34°). This amplitude lies out…
- [exam] A physicist measures two pendulums at the same location. Pendulum 1 has length L₁ = 0.50 m and measu…