EQUATION

Coupled Pendulum Normal Modes

Gives the two normal-mode frequencies of two identical pendulums coupled by a weak spring: ω₁ = ω₀ (in-phase, spring unstretched) and ω₂ = √(ω₀² + ω_C²) (anti-phase, spring stretched)

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The equation

EQ.COUPLED-NORMAL-MODES
\omega_1 = \omega_0,\quad \omega_2 = \sqrt{\omega_0^2 + \omega_C^2}
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What it solves

Gives the two normal-mode frequencies of two identical pendulums coupled by a weak spring: ω₁ = ω₀ (in-phase, spring unstretched) and ω₂ = √(ω₀² + ω_C²) (anti-phase, spring stretched). Beats arise at frequency (ω₂ − ω₁)/2.

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When to use it

Two identical pendulums (or oscillators) linked by a coupling spring or shared element. The general motion is a superposition of the two normal modes with amplitudes set by initial conditions.

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When NOT to use it

The simple two-mode formula applies only when both oscillators are identical. Non-identical oscillators have normal mode frequencies that depend on both natural frequencies and the coupling; the full eigenvalue problem must be solved.

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Common mistakes

Forgetting that normal modes are collective motions, not individual oscillator motions. Computing ω_C from the coupling spring stiffness k_C incorrectly — for pendulums, ω_C² = 2k_C/m. Describing beats as a third mode rather than as interference between the two normal modes.

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Topics that use this equation

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Problems using this equation