Complete Elliptic Integral of the First Kind
Defines K(k) = ∫₀^{π/2} dφ / √(1 − k²sin²φ), a definite integral that appears in the exact large-angle pendulum period and many other physics problems
The equation
What it solves
Defines K(k) = ∫₀^{π/2} dφ / √(1 − k²sin²φ), a definite integral that appears in the exact large-angle pendulum period and many other physics problems. Numerically, K(0) = π/2 and K grows as k → 1.
When to use it
Evaluating the exact pendulum period for large angles. K(k) is available in most scientific libraries (Python: scipy.special.ellipk; Mathematica: EllipticK). The AGM algorithm converges in ~10 iterations.
When NOT to use it
K diverges logarithmically as k → 1 (pendulum amplitude → 180°) — the pendulum takes infinite time to reach the inverted position. For small k, the series K(k) ≈ π/2·(1 + k²/4 + 9k⁴/64 + …) is simpler.
Common mistakes
Passing k² to functions that expect k (or vice versa) — check each library's convention. Confusing K(k) (first kind) with E(k) (second kind). Evaluating the integral in degrees instead of the proper half-period 0 to π/2 in radians.
Topics that use this equation
Problems using this equation
- [challenge] A pendulum is released from rest at θ₀ = 1.0 rad (≈ 57.3°) and its period is measured to be T = 3.0 …
- [exam] A clock pendulum of length L = 1.0 m is pulled to θ₀ = 1.4 rad (≈ 80.2°) and released. (a) Compute t…
- [hard] A pendulum of length L = 2.0 m is released from rest at θ₀ = 1.2 rad (≈ 68.8°). (a) Find the ellipti…