EQUATION

Projectile Range

Gives the horizontal distance a projectile travels before returning to its launch height

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The equation

EQ.PROJECTILE-RANGE
R = \frac{v_0^2\sin 2\theta}{g}
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What it solves

Gives the horizontal distance a projectile travels before returning to its launch height. Optimal range occurs at θ = 45°; complementary angles (e.g., 30° and 60°) give equal ranges.

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When to use it

Level-ground projectile problems with no air resistance and constant g. The sin(2θ) form is compact but requires the angle to be measured from horizontal.

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When NOT to use it

Invalid for uneven terrain (launch ≠ land height). Breaks down with air drag — real maximum-range angles are less than 45°. Do not use on inclined planes without re-deriving the formula.

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Common mistakes

Using sin θ instead of sin 2θ — a very common algebra slip. Not recognizing that sin 2θ = sin(180° − 2θ), which means two angles give the same range. Plugging in g = 10 when the problem specifies 9.8 m/s² or 9.81 m/s².

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Topics that use this equation

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Problems using this equation