Position–Time Relation
Gives the displacement of an object under constant acceleration after a time t
The equation
What it solves
Gives the displacement of an object under constant acceleration after a time t. Use it when you need distance traveled and do not know — or want to avoid finding — the final velocity.
When to use it
Constant-acceleration rectilinear motion. Applies equally to vertical free-fall (a = g downward) and horizontal braking problems.
When NOT to use it
Breaks down when acceleration changes with time. Gives displacement, not total path length, so it can mislead if the object reverses direction.
Common mistakes
Using total time T instead of the sub-interval time t. Forgetting the ½ factor, which doubles the answer. Substituting distance for displacement — if the object turns around, the equation still gives the net displacement, not the odometer reading.
Topics that use this equation
Problems using this equation
- [medium] A train leaves a station at 5 m/s and accelerates uniformly at 2 m/s² for 12 seconds. Find the train…
- [hard] A driver is travelling at 30 m/s when they spot a hazard. Their reaction time is 0.8 s, after which …
- [exam] Car B has a 50 m head start and moves at a constant 15 m/s. Car A starts from rest at the same momen…