EQUATION

Projectile Peak Height

Gives the maximum height reached by a projectile above its launch point

§ 01

The equation

EQ.PROJECTILE-PEAK-HEIGHT
H = \frac{(v_0\sin\theta)^2}{2g}
§ 02

What it solves

Gives the maximum height reached by a projectile above its launch point. At the peak, the vertical velocity component is zero; only v_x remains.

§ 03

When to use it

Level-ground projectile launch with constant g and no drag. Also valid for off-level launches if H is measured from the launch height, not the ground.

§ 04

When NOT to use it

Does not apply when the object is launched from an elevated platform and lands below — the geometric peak may still be the same, but measuring from a reference other than launch height requires care. Drag lowers the peak.

§ 05

Common mistakes

Using v_0 (total speed) instead of v_0·sin θ (vertical component). Forgetting to square the entire vertical component before dividing by 2g. Mixing up H (height above launch) with the height above ground when the launch is elevated.

§ 06

Topics that use this equation

§ 07

Problems using this equation