EXAM · OSCILLATORS EVERYWHERE
SHM POSITION VELOCITY ACCELERATION
A 0.5 kg block on a spring oscillates with amplitude A = 0.20 m, angular frequency ω = 4.0 rad/s, and initial phase φ = π/3 rad, so its position is x(t) = A cos(ωt + φ). At t = 0.80 s, find: (a) position x, (b) velocity v, (c) acceleration a. Then verify energy conservation by computing the kinetic energy KE, potential energy PE, and total mechanical energy E, confirming KE + PE = E.
Linked equations:x'' + \omega^2 x = 0x(t) = A\cos(\omega t + \phi)v(t) = -A\omega\sin(\omega t + \phi)a(t) = -A\omega^2\cos(\omega t + \phi)E = \tfrac{1}{2}kA^2
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Step-by-step solution
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Step 1
From ω = √(k/m), find the spring constant k.
Hint
Rearrange to k = mω². This lets you compute PE = ½kx² later.
Step 2
Write x(t) = A cos(ωt + φ) and evaluate at t = 0.80 s. What is the argument ωt + φ in radians?
Step 3
Differentiate x(t) = A cos(ωt + φ) to get velocity v(t). Evaluate at t = 0.80 s.
Step 4
Differentiate v(t) to find acceleration a(t). Evaluate at t = 0.80 s.
Step 5
The total mechanical energy is conserved and equals ½kA². Compute E.
Solution walkthrough
Simple harmonic motion carries three kinematic descriptions simultaneously — position, velocity, and acceleration — each a sinusoid at the same frequency but phase-shifted by 90° from the previous. Starting from x(t) = A cos(ωt + φ), one differentiation gives v(t) = −Aω sin(ωt + φ), and a second gives a(t) = −Aω² cos(ωt + φ) = −ω²x. That last equality is Newton's second law: F = ma = −mω²x = −kx. At t = 0.8 s, the phase angle is ωt + φ = 4 × 0.8 + π/3 ≈ 4.247 rad. cos(4.247) ≈ −0.738, sin(4.247) ≈ −0.675. So x = 0.2 × (−0.738) ≈ −0.148 m, v = −0.2 × 4 × (−0.675) ≈ +0.540 m/s, a = −0.2 × 16 × (−0.738) ≈ +2.36 m/s². Energy: k = mω² = 0.5 × 16 = 8 N/m, so E = ½ × 8 × 0.04 = 0.16 J. At this instant, KE = ½ × 0.5 × 0.540² ≈ 0.073 J and PE = ½ × 8 × 0.148² ≈ 0.088 J. Their sum is ≈ 0.161 J — rounding precision away, this agrees with E = 0.16 J. The small discrepancy is purely from rounding the phase; the exact algebra always gives KE + PE = ½kA². That invariance — energy shared between kinetic and potential but always summing to the same total — is what makes SHM a conservative system.
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