EASY · NEWTONS THREE LAWS

ACCELERATION FROM NET FORCE

A 5 kg box sits on a frictionless surface. A single horizontal force of 30 N is applied to it. What is the acceleration of the box?

Linked equations:F = ma
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Step-by-step solution

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Step 1

Apply Newton's second law to find the acceleration.

Hint

The net force equals the applied force because there is no friction. Divide net force by mass.

Solution walkthrough
Newton's second law states that the net force acting on an object equals its mass multiplied by its acceleration: F = ma. Here the surface is frictionless, so the only horizontal force is the applied 30 N push. There is no opposing friction to subtract. The net force is therefore exactly 30 N. Rearranging the second law gives a = F/m. Substituting the known values: a = 30 N ÷ 5 kg = 6 m/s². The direction of the acceleration matches the direction of the force — the box speeds up in the direction it was pushed. This is the purest expression of the second law: one force, one mass, one acceleration. The number 6 m/s² means that every second the box is gaining 6 metres per second of speed. In two seconds it would be moving at 12 m/s; in three seconds, 18 m/s — and so on, for as long as the force is applied. A common error is to confuse the box's weight (mg = 5 × 9.8 ≈ 49 N) with the applied force. Weight acts downward and is balanced by the normal force from the surface; it plays no role in the horizontal acceleration. Another trap is inverting the fraction and computing m/F = 5/30 ≈ 0.17, which gives units of kg/N — not m/s².
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